Solve [math]x^2 + 2x + 1 = 0[/math]?
Factorise the equation first:
Find two numbers that multiply to give you 1, and add to give you 2:
Both numbers are 1, therefore
[math]x^2 + 2x + 1 = (x + 1)(x + 1) = (x + 1)^2[/math]
To solve, make the equation equal to 0:
[math](x + 1)(x + 1) = 0[/math]
Therefore our answer is [math]x = -1[/math]
We call this a repeated root.